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Direct integration initial value problems

#027

Problem

y=3x2,y(1)=5y' = 3x^2,\quad y(1)=5

Classification

  • power rule
  • initial condition

Method

  • direct integration
  • initial value problem

Solution

y=x3+4y = x^3 + 4

Simulation & Code

Computational workSimulation
Graph visualization for entry #027
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Python codeOpen
import numpy as np
import matplotlib.pyplot as plt

x = np.linspace(-3, 3, 800)

with np.errstate(divide="ignore", invalid="ignore", over="ignore"):
    y = x**3 + 4
    y_prime = 3*x**2

plt.figure(figsize=(8, 5))
plt.plot(x, y, label="y = x^3 + 4", linewidth=2)
plt.plot(x, y_prime, label="y' = 3x^2", linewidth=2, color="red")
plt.title("Entry #027: solution and derivative")
plt.xlabel("x")
plt.ylabel("value")
plt.grid(True, alpha=0.35)
plt.legend()
plt.tight_layout()
plt.show()

Handwritten derivation

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Takeaway & Interpretation

The differential equation tells us that the slope is 3x^2. After using integration, we can pinpoint the solution because the initial condition tells us y(1)=5.