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Direct integration initial value problems

#041

Problem

y=3x+2ex,y(0)=5y' = 3\sqrt{x} + 2e^x,\quad y(0)=5

Classification

  • power rule
  • exponential antiderivative
  • domain restriction
  • initial condition

Method

  • direct integration
  • initial value problem

Solution

y=2x3/2+2ex+3y = 2x^{3/2} + 2e^x + 3

Simulation & Code

Computational workSimulation
Graph visualization for entry #041
Download .py file
Python codeOpen
import numpy as np
import matplotlib.pyplot as plt

x = np.linspace(0, 4, 800)

with np.errstate(divide="ignore", invalid="ignore", over="ignore"):
    y = 2*x**1.5 + 2*np.exp(x) + 3
    y_prime = 3*np.sqrt(x) + 2*np.exp(x)

plt.figure(figsize=(8, 5))
plt.plot(x, y, label="y = 2x^(3/2) + 2e^x + 3", linewidth=2)
plt.plot(x, y_prime, label="y' = 3sqrt(x) + 2e^x", linewidth=2, color="red")
plt.title("Entry #041: solution and derivative")
plt.xlabel("x")
plt.ylabel("value")
plt.grid(True, alpha=0.35)
plt.legend()
plt.tight_layout()
plt.show()

Handwritten derivation

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Takeaway & Interpretation

The differential equation tells us that the slope is 3sqrt(x) + 2e^x. After using integration, we can pinpoint the solution because the initial condition tells us y(0)=5.