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Direct integration initial value problems

#029

Problem

y=x2,y(1)=0y' = x^{-2},\quad y(1)=0

Classification

  • power rule
  • domain restriction
  • initial condition

Method

  • direct integration
  • initial value problem

Solution

y=1x+1y = -\frac{1}{x} + 1

Simulation & Code

Computational workSimulation
Graph visualization for entry #029
Download .py file
Python codeOpen
import numpy as np
import matplotlib.pyplot as plt

x = np.linspace(-5, 5, 800)

with np.errstate(divide="ignore", invalid="ignore", over="ignore"):
    y = -1/x + 1
    y_prime = x**-2


def mask(values, limit=100):
    return np.where(np.isfinite(values) & (np.abs(values) <= limit), values, np.nan)

y = mask(y)
y_prime = mask(y_prime)
plt.figure(figsize=(8, 5))
plt.plot(x, y, label="y = -1/x + 1", linewidth=2)
plt.plot(x, y_prime, label="y' = x^(-2)", linewidth=2, color="red")
plt.title("Entry #029: solution and derivative")
plt.xlabel("x")
plt.ylabel("value")
plt.grid(True, alpha=0.35)
plt.legend()
plt.tight_layout()
plt.show()

Handwritten derivation

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Takeaway & Interpretation

The differential equation tells us that the slope is x^(-2). After using integration, we can pinpoint the solution because the initial condition tells us y(1)=0. This differential equation has a singularity at x=0.