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Direct integration initial value problems

#030

Problem

y=4x,y(0)=2y' = 4\sqrt{x},\quad y(0)=2

Classification

  • power rule
  • domain restriction
  • initial condition

Method

  • direct integration
  • initial value problem

Solution

y=83x3/2+2y = \frac{8}{3}x^{3/2} + 2

Simulation & Code

Computational workSimulation
Graph visualization for entry #030
Download .py file
Python codeOpen
import numpy as np
import matplotlib.pyplot as plt

x = np.linspace(0, 6, 800)

with np.errstate(divide="ignore", invalid="ignore", over="ignore"):
    y = (8/3)*x**1.5 + 2
    y_prime = 4*np.sqrt(x)

plt.figure(figsize=(8, 5))
plt.plot(x, y, label="y = (8/3)x^(3/2) + 2", linewidth=2)
plt.plot(x, y_prime, label="y' = 4sqrt(x)", linewidth=2, color="red")
plt.title("Entry #030: solution and derivative")
plt.xlabel("x")
plt.ylabel("value")
plt.grid(True, alpha=0.35)
plt.legend()
plt.tight_layout()
plt.show()

Handwritten derivation

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Takeaway & Interpretation

The differential equation tells us that the slope is 4sqrt(x). After using integration, we can pinpoint the solution because the initial condition tells us y(0)=2. This differential equation only takes positive values, this means the slope of the solution is always positive.